what is remainder when 123412431234...(400 digits) is divided by 909?

• 1234%909=325;
  12341234%909=650=325*2;
  123412341234%909=325*3;
  ..
  ..
  ..
  ..
  ..
  ..
  12341234....................(repetation of 1234 100 times)=325*100=32500;
  therefore,32500%909=685; that's it.
  Always observe the pattern when there id periodic repetaion of digit are there.
• 10 years agoHelpfull: Yes(22) No(1)
• if you divide 1234 by 909 u get remainder 325
  
  so if u divide 100* 325 / 909 the remainder will be the same
  
  32500/909 gives remainder 685
  
  685 is the answer
  if we divide 1234 by 909 the remainder will be 325.
  now we have to do this 100 times.
  so 32500/909 gives 685.
  or...
  32500/909 the integer part is 35
  32500 - 35 * 909 = 32500 -31815 = 685
• 10 years agoHelpfull: Yes(12) No(4)
• 1234/909=325*1
  12341234/909=650=325*2
  123412341234/909=(325*3)/909=66
  1234123412341234/909=(325*4)/909=391
  similarly
  .......
  ..........
  .............
  123412341234...(400 digits) means 1234 100 times,so
  123412431234...(400 digits)/909=325*100=32500
  now dividing 32500 by 909 gives the reqd remainder which is 685
• 10 years agoHelpfull: Yes(7) No(1)
• 4 numbers "1234"placed after each...so in 400 digits the 4 digits from the last should be 1234...so 1234/909 is 325..so the answer should be 325..
• 10 years agoHelpfull: Yes(1) No(1)
• if 12341243/909 gives remainder=659
  nd its occurs 50 times
  so 659*50=32950
  nd 32950/909=226
  so ans is226
• 10 years agoHelpfull: Yes(1) No(2)
• 1234 occur 100 times so remainder will be 100*1234 mod 909=685
• 10 years agoHelpfull: Yes(1) No(2)
• The ques is wrong if you carefully see the ques..The seventh digit should be 3 and the eight digit should be 4..
• 10 years agoHelpfull: Yes(1) No(0)
• The remainder is 685 !!!
• 10 years agoHelpfull: Yes(1) No(0)