what is last digit of 62^43^54^65^&76^87 ?

• 76^87=4k+2
  65^(4k+2)=65^4k+65^2=65^4k+1225/100=4k+1
  54^(4k+1)=54^4k+54^1=4k+2
  43^(4k+2)=43^4k+43^2=4k+1
  62^4k+1
  cycle of 2 is 4
  2^1=2
  ans)2
• 10 years agoHelpfull: Yes(2) No(1)