An unbiased coin is tossed 7 times,find the chance that exactly 5 times head will appear?

• 7C5/2^7 gives u the required answer
• 11 years agoHelpfull: Yes(36) No(2)
• I think the answer is (1/2)^7
• 11 years agoHelpfull: Yes(3) No(3)
• the ans is 7c5*1/2^5*1/2^2
• 11 years agoHelpfull: Yes(2) No(0)
• ans is (7c5*1/2)/2^7.probability of choosing a head is 1/2 and probability of 5 heads out of 7 outcomes is 7c5. so according to me this is right answer.
• 11 years agoHelpfull: Yes(1) No(0)
• 5/14
  14 is the total number of probability
  
• 11 years agoHelpfull: Yes(0) No(3)
• 7c5*(1/2)^5
• 11 years agoHelpfull: Yes(0) No(1)
• @brijesh...can u explain that how u r getting 7C5?
• 11 years agoHelpfull: Yes(0) No(0)
• 21/2^7 is the ans
• 11 years agoHelpfull: Yes(0) No(0)
• its 7!/2^7 because the logic is we have to just get the head exactly 5 times.thats the key.the order is not important.we just need to have 5 exact heads,thats it
• 11 years agoHelpfull: Yes(0) No(0)
• (1/2)^7/2^7
• 11 years agoHelpfull: Yes(0) No(0)
• 7C5*(1/2)^7
• 11 years agoHelpfull: Yes(0) No(0)
• the ans is 7c5/2^5
• 10 years agoHelpfull: Yes(0) No(0)