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If 28a + 30b+ 31c=365, find the value of a+b+c, if a, b, and c are natural numbers.
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- Nice question!!
This ques is related to the no of days of a month in an ordinary(non leap) year.
i.e.,28 days of feb(a=1);30 days of apr,jun,spt,nov(b=4) and 31 days of the rem months(c=7).
Hence a+b+c=1+4+7=12. - 11 years agoHelpfull: Yes(55) No(0)
- we obserb that there are 365 days in a general year
feb=28 days
there are 4 months with 30 days(apr,june,sep,nov)
& 7 months with 31 days(jan,mar,may,jul,aug,oct,dec)
so a=1
b=4
c=7
so a+b+c=1+4+7=12 - 11 years agoHelpfull: Yes(12) No(0)
- 28x1 + 30x4 +31x7 = 365
a+b+c= 1+4+7= 12
solved using hit n trial or as a non leap year question
28 days of feb(a=1);30 days of apr,jun,spt,nov(b=4) and 31 days of the rem months(c=7) - 11 years agoHelpfull: Yes(4) No(0)
- answer is 12
because i month is of 28 days that is february s
4 months of 30 days so b=4 and 7 months of 31 days so c=7
so 4+7+1=12 - 11 years agoHelpfull: Yes(3) No(0)
- it is the ques based on calender months..if we seeing the equation ,28 day in feb month,30 days in 4 month(apr,jul,sep,nov),and for 31 days in remaining 7 months so the solution will be 1,4,7, :)
- 11 years agoHelpfull: Yes(0) No(0)
- 12
- 11 years agoHelpfull: Yes(0) No(0)
- 1+4+7=12
1 for feb.
4 for 30 days months
and 7 for 31 daya months
and finally add them. - 11 years agoHelpfull: Yes(0) No(0)
- a+b+c=9
ans.a=4,b=2,c=3 - 11 years agoHelpfull: Yes(0) No(2)
- ans is 425
- 11 years agoHelpfull: Yes(0) No(2)
- a+b+c=4+5+3=12
so,(28*4)+(30*5)+(31*3)=365
- 11 years agoHelpfull: Yes(0) No(0)
- answer is 12 because of in one year have 28 days in febrary and 30 days in 5 months and 31 days in 6 months so 1+5+6=12
- 8 years agoHelpfull: Yes(0) No(0)
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