If 28a + 30b+ 31c=365, find the value of a+b+c, if a, b, and c are natural numbers.

• Nice question!!
  This ques is related to the no of days of a month in an ordinary(non leap) year.
  i.e.,28 days of feb(a=1);30 days of apr,jun,spt,nov(b=4) and 31 days of the rem months(c=7).
  Hence a+b+c=1+4+7=12.
• 10 years agoHelpfull: Yes(55) No(0)
• we obserb that there are 365 days in a general year
  feb=28 days
  there are 4 months with 30 days(apr,june,sep,nov)
  & 7 months with 31 days(jan,mar,may,jul,aug,oct,dec)
  so a=1
  b=4
  c=7
  so a+b+c=1+4+7=12
• 10 years agoHelpfull: Yes(12) No(0)
• 28x1 + 30x4 +31x7 = 365
  a+b+c= 1+4+7= 12
  
  solved using hit n trial or as a non leap year question
  28 days of feb(a=1);30 days of apr,jun,spt,nov(b=4) and 31 days of the rem months(c=7)
• 10 years agoHelpfull: Yes(4) No(0)
• answer is 12
  because i month is of 28 days that is february s
  4 months of 30 days so b=4 and 7 months of 31 days so c=7
  so 4+7+1=12
• 10 years agoHelpfull: Yes(3) No(0)
• it is the ques based on calender months..if we seeing the equation ,28 day in feb month,30 days in 4 month(apr,jul,sep,nov),and for 31 days in remaining 7 months so the solution will be 1,4,7, :)
• 10 years agoHelpfull: Yes(0) No(0)
• 12
• 10 years agoHelpfull: Yes(0) No(0)
• 1+4+7=12
  1 for feb.
  4 for 30 days months
  and 7 for 31 daya months
  and finally add them.
• 10 years agoHelpfull: Yes(0) No(0)
• a+b+c=9
  ans.a=4,b=2,c=3
• 10 years agoHelpfull: Yes(0) No(2)
• ans is 425
• 10 years agoHelpfull: Yes(0) No(2)
• a+b+c=4+5+3=12
  so,(28*4)+(30*5)+(31*3)=365
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• answer is 12 because of in one year have 28 days in febrary and 30 days in 5 months and 31 days in 6 months so 1+5+6=12
• 7 years agoHelpfull: Yes(0) No(0)