there are 7 people in a room then wat is d probability dat 2 of dem hv same birthdy

365*365*364*363*362*361*360/(365)^7= 0.02
11 years agoHelpfull: Yes(4) No(3)
Total people = 7
People having same birthday = 2
So the probability is 2/7 (Favorable events / Total possible events).
11 years agoHelpfull: Yes(2) No(5)
365*365*364*363*362*361*360/365^7
11 years agoHelpfull: Yes(2) No(0)
7c2*365*364*363*362*361*360/(365)^7
11 years agoHelpfull: Yes(2) No(0)
out of 7 2 people can be chosed in 7c2=7*6/2
and d prob. of same brdy is (1/7)^2*7*6/2=6/14
11 years agoHelpfull: Yes(1) No(3)
can u pls elaborate it?
11 years agoHelpfull: Yes(1) No(2)
selecting two peoples from thr grp of 7 is,, 7c2 ...(1)
now, selecting a common day for those two guy's bday is 7c1.. (2)
and the other 5 peoples chooses the remaining 5 days out of 6 days in,, 6c5*5!. (3)
now, number of ways 7 peoples can be born on 7 days in 7^7
hence answer will be,,, {(1)*(2)*(3)}/7^7
== (7c1*7c2*6c5*5!)/7^7
11 years agoHelpfull: Yes(1) No(3)
pls explain
11 years agoHelpfull: Yes(0) No(1)

there are 7 people in a room then wat is d probability dat 2 of dem hv same birthdy?