A boy has several coloured balls in his bag - 12 white 15 orange and 25 pink The lights are

first he collect 1 ball of each colour when he take out next ball first pair comes out
so 25 + 15+2=42 ans
10 years agoHelpfull: Yes(14) No(7)

The solution can be derived as:
Since out of 25 pink, 15 orange, 12 white balls,there are maximum number of pink balls so up to the 25th ball also we would not be sure that we have got a pair of each.
So, We must take out 25 balls.
Even still taking out 27 balls also does not guarantee us,that the required condition is met.So,
The minimum number of balls to be drawn=25+15+2=42.
Since after withdrawing the 42nd ball we are 100% that we exhausted both the possibilities of withdrawing orange and pink balls ans we a pair of each ball with different colour.
10 years agoHelpfull: Yes(6) No(1)
Take all 25+15+2, so that either of the counting will consist of 12 white, 15 orange and 25 pink balls

so 25 + 15+2=42 ans
10 years agoHelpfull: Yes(1) No(0)
ans=42. we have to take worst possible case in these type of qn. so max. way=(25+15+2)=42
10 years agoHelpfull: Yes(1) No(0)
here options are givn odrwise it can have 3 ans 29 ,39,42
10 years agoHelpfull: Yes(1) No(0)
42 to be 100% sure and (12+15+2)=29 can also give 2 pairs of each type
10 years agoHelpfull: Yes(0) No(1)
42
10 years agoHelpfull: Yes(0) No(0)
he must take out all 42 (12+15+25).. now he can make sure that he has a pair of each color....
10 years agoHelpfull: Yes(0) No(0)
25 + 15+2=42
10 years agoHelpfull: Yes(0) No(0)
SHORT CUT:
highest value+next value +2
25+15+2
=42
10 years agoHelpfull: Yes(0) No(0)

A boy has several coloured balls in his bag - 12 white, 15 orange and 25 pink. The lights are out and it is totally dark. Now, how many balls he must take out to make sure that he has a pair of each color? a)40 b)42 c)6 d)12