C Programming and Technical

output?
main()
{
char string[]="Hello World";
display(string);
}
void display(char *string)
{
printf("%s",string);
}
Answer: Compiler Error: Type mismatch in redeclaration of function display
Explanation: In third line, when the function display is encountered, the compiler doesn't know
anything about the function display. It assumes the arguments and return types to be integers,
(which is the default type). When it sees the actual function display, the arguments and type
contradicts with what it has assumed previously. Hence a compile time error occurs

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C Other Question

output??
main()
{
printf("%x",-1
main()
{i
nt c=- -2;
printf("c=%d",c);
}
Answer: c=2;
Explanation: Here unary minus (or negation) operator is used twice. Same maths rules applies,
ie. minus * minus= plus.
Note: However you cannot give like --2. Because -- operator can only be applied to variables as
a decrement operator (eg., i--). 2 is a constant and not a variable