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Height and Distance
From the top of a 9 meters high building AB,the angle of elevation of the top of tower CD is 30 and the angle of depression of the foot of the tower is 60. what is the height of the tower?
Read Solution (Total 6)
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- let h be the height of tower,y be the distance betn tower & building
draw the diagram
tan60=9/y
or y=9/tan60
also, tan30=(h-9)/y
or y*tan30=h-9
or (9/tan60)*tan30=h-9
or 9/3=h-9
or 3=h-9
hence h=12
- 10 years agoHelpfull: Yes(23) No(1)
- height of tower=12m.
- 10 years agoHelpfull: Yes(3) No(0)
- ans=12 meter
- 10 years agoHelpfull: Yes(3) No(0)
- 9 + 3
that is 12 - 10 years agoHelpfull: Yes(1) No(0)
- tan60 = 9/BD
BD=3*sqrt(3)
again
tan30 = (9-CD)/3*sqrt(3)
CD= 6meters - 10 years agoHelpfull: Yes(0) No(4)
- AB=9 m.angle of depression=60 degree= similar angle tothe base.now angle
- 10 years agoHelpfull: Yes(0) No(1)
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