In how many ways a 11 letter word can be formed where the even places r occupied by vowels and odd places r occupied by consonants?

• In a 11 letter words the odd places are (1,3,5,7,9,11) ..and even places (2,4,6,8,10)..
  vowels = 5,and consonant=21
  So,We can place vowels in 5 even places by 5! ways...
  Now,to fill remaining places ,the 6 consonant can be chosen from 21 by 21c6 ways..and they can be arranged as 6! ways..
  
  So,Number of Ways=5!*21c6*6!
  
  
  
• 10 years agoHelpfull: Yes(51) No(4)
• 21^6*5^5 ans.if letters are repeted.
  21*20*19*18*17*16*5*4*3*2*1 ans if letters are not repeted.
  
• 10 years agoHelpfull: Yes(25) No(3)
• 5p5 * 21p6
• 10 years agoHelpfull: Yes(8) No(0)
• 1. if repetition is allowed
  ans= 5^5*21^6
  2. if repetition is not allowed
  ans= 5!*21C6*6!
• 10 years agoHelpfull: Yes(2) No(0)
• if its not mention then it would be like replication is allowed
  21^6*5^5
• 10 years agoHelpfull: Yes(1) No(0)
• 5 even places and 6 odd places
  5 vowels can be arranged in 5! ways and 21 consonants can be arranged in 21P6 ways
  hence total = 5! * 21P6
• 10 years agoHelpfull: Yes(1) No(0)
• when repitation not allowed 5!*21c6*6!
  ,,,,,,,,,,,,,,,, allowed 5!*5!*5!*5!*5!*6*6!
• 10 years agoHelpfull: Yes(0) No(1)
• 5!*6!=86400(ans)
• 10 years agoHelpfull: Yes(0) No(1)
• 21!6!/5!*5!
  this will be the answer
• 10 years agoHelpfull: Yes(0) No(0)
• 5!*6!
  5 vowels can be arranged in 5! ways..
  6 consonants which are already fixed can be arranged in 6! ways
  so 5!*6!
• 10 years agoHelpfull: Yes(0) No(0)
• 21^6*5^5
• 10 years agoHelpfull: Yes(0) No(1)
• 5!*21c6*6!*11!
  
• 9 years agoHelpfull: Yes(0) No(0)