If the lcm of 2 natural numbers A and B is 1260, what is the minimum possible value of A+B ?

• LCM 1260 can be written as 2*2*3*3*5*7=36*35=28*45=42*30=....
  (These are in the form of A*B)
  so minimum value should be A+b=35+36=71 :)
• 11 years agoHelpfull: Yes(39) No(1)
• the lcm of no's A and B=1260(given)and it can be expressed as 2*2*3*3*5*7=28*46=42*30=35*36 =(A*B)
  so,the minimum value of A+B is =35+36=71 ans.
• 11 years agoHelpfull: Yes(5) No(1)
• 28
  3*3*3*3*2*2*5*7 will be the factors.
• 11 years agoHelpfull: Yes(1) No(7)
• MInimum possible value of A+B= 35+36 = 71 Ans.
• 11 years agoHelpfull: Yes(1) No(0)
• 83= 20+63
  
• 11 years agoHelpfull: Yes(1) No(2)