CAT
Exam
The total number of prime factors of (402)^7 is
Read Solution (Total 3)
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- 8*8*8=512=no of factors
- 11 years agoHelpfull: Yes(1) No(0)
- 402=2*3*67
hence 3...
- 11 years agoHelpfull: Yes(1) No(0)
- (402)^7 =2^7 * 3^7 * (67)^7
=>total no of factors=(7+1)(7+1)(7+1)=512 - 11 years agoHelpfull: Yes(0) No(1)
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