If N=A*A*B*C .Then how many factors of N are there?

• A^2 * B^1 * C^1
  so the no.of factors is (2+1)(1+1)(1+1)= 12 factors
• 11 years agoHelpfull: Yes(16) No(2)
• 12 ONLY IF A,B,C ARE PRIME
  
• 11 years agoHelpfull: Yes(5) No(2)
• (2+1)*(1+1)*(1+1)=12
• 11 years agoHelpfull: Yes(3) No(2)
• 1,a,a^2,b,c,ab,ac,bc,a^2*b,a^2*c,abc,aabc
  12 factors.
• 11 years agoHelpfull: Yes(1) No(2)
• no of factors=3*2*2=12
• 11 years agoHelpfull: Yes(1) No(2)
• 12
• 11 years agoHelpfull: Yes(1) No(1)
• N=A^2 * B * C
  number of factors=(2+1)*(1+1)*(1+1)=12
• 11 years agoHelpfull: Yes(1) No(1)
• 12=
  ans.
  factors
• 11 years agoHelpfull: Yes(1) No(0)
• We can re-write N as,
  N=A^2*B*C
  Thus, No. of factors of N are,
  N=(2+1)*(1+1)*(1+1)
  =3*2*2
  =12
  No. of factors of N are 12.
• 11 years agoHelpfull: Yes(0) No(1)
• A^2*B^1*C^1
  i.e No.of factors=(2+1)*(1+1)*(1+1)=12
• 11 years agoHelpfull: Yes(0) No(1)