There is a pool of radius X and there is a path way around the pool with a width of

(PI.(X+4)^2-PI.X^2)/PI.X^2=11/25
(X+4)^2/X^2-1=11/25
(X+4)^2/X^2=36/25
(X+4)/X=6/5
X=20
10 years agoHelpfull: Yes(46) No(3)

its just a dummy ques ... as unit of pool's radius is not mentioned so you can equate it with "feet"......... asked in tcs in some colleges of south.. :)
10 years agoHelpfull: Yes(6) No(8)
Let pool radius=r
pi*(x+4)^2 - pi*r^2=pi*r^2 * 11/25
x=20
so radius of pool=20 feet.
10 years agoHelpfull: Yes(3) No(0)
(r+4)^2 - r^2 /r^2 =11/25
(r+4)^2 /r^2 = 11/25 +1
((r+4)/r)^2 = 36/25
(r+4) / r = sqrt(36 /25 )
(r+ 4) / r =6 /5
5r + 20 = 6r
r =20
8 years agoHelpfull: Yes(3) No(0)
pi(x+4)^2-pix^2/pix^2=11/25
solve x
10 years agoHelpfull: Yes(1) No(2)
ans is 20,which is not given above..
10 years agoHelpfull: Yes(1) No(0)
bnate bnate haalt khrab ho gya answer 20feet nikala tha..
fir v solve dubara se bnate ja rhe the..niche dekha tb pta chla ki option hi glt dala gya h.. so guys please update question with correct options...
10 years agoHelpfull: Yes(1) No(1)
Ans 20
(pi(X+4)^2-pi(X)^2)/pi(X)^2=11/25
on solving we get x=20
10 years agoHelpfull: Yes(1) No(0)
ans is 25
8 years agoHelpfull: Yes(1) No(2)
ans [pi{(x+4)^-x^2}]/pi x^2=11/25
then solving we get x=20 feet
10 years agoHelpfull: Yes(0) No(0)
ans is (a)12
10 years agoHelpfull: Yes(0) No(7)
x=20 which is not given in options :p
10 years agoHelpfull: Yes(0) No(1)
[pi{(x+4)^-x^2}]/pi x^2=11/25
so x = 20
10 years agoHelpfull: Yes(0) No(2)
X=20
10 years agoHelpfull: Yes(0) No(0)
yes 20 is the correct
10 years agoHelpfull: Yes(0) No(0)

There is a pool of radius X and there is a path way around the pool with a width of 4 feet. Find the radius of the pool if the path area / pool area = 11/25

Option
a) 12
b) 5
c) 25
d) 29