1! + 2! + 3! + 4! +.......50!

• Ans=
  =>50!(1!/50! +2!/50!+.......49!/50! + 50!/50!)
  =>first 48 terms are negligible ,thus eq becomes
  =>50!(49!/50! +1)
  =>50!(1/50 +1)
  =>50!(1.02)
  =>50!*102/100
  =>50!*51/50
  =>51!/50
• 11 years agoHelpfull: Yes(40) No(1)
• 1!+2!+3!+...+n! = (n+1)!/n
• 11 years agoHelpfull: Yes(11) No(1)
• 50!-1 Ans.
• 11 years agoHelpfull: Yes(4) No(8)
• 50!(1+1/50+1/(50*49)....)
  =50!(1+1/50) [other terms are negligible]
  50!*1.02
• 11 years agoHelpfull: Yes(3) No(5)
• the question must be... what is the last digit of this number....kind of...
• 11 years agoHelpfull: Yes(1) No(2)
• this puzzle cant b solved, it is incorrect.it is a remainder type question.
  
  
• 11 years agoHelpfull: Yes(0) No(8)
• 51!/50
• 11 years agoHelpfull: Yes(0) No(1)
• 4 yrs ago average age is 45
  nw 4*4=16one join 49 age
  so avrge 49
  
• 11 years agoHelpfull: Yes(0) No(2)
• 1!+2!+3!........n!;we have the formula that sum of n! is (n+1)!/n;
  so by using that (50+1)!/50=51!/50=49!*51
• 11 years agoHelpfull: Yes(0) No(1)
• approx.....50!*50/49 by n!*n/(n-1)
• 11 years agoHelpfull: Yes(0) No(0)