This is a simple Number System Problem, posted under Placement Category

Let x, y and z be distinct integers. x and y are odd and positive, and z is even and positive. Which one of the following statements cannot be true?

1)(x-z)2 y is even 2)(x-z)y2 is odd 3) (x-z)y is odd 4)(x-y)2z is even

• here i think sir first is incorrect
  As it given x and y is odd and z is even
  odd - even always = odd
  odd square is odd
  odd* odd is odd
  but its given its even
  so 1 is incorrect sir
  and thanks space for my problem
• 13 years agoHelpfull: Yes(0) No(2)
• i agree with Ankit .first one is incorrect
  
• 11 years agoHelpfull: Yes(0) No(0)