Gate
Exam
Logical Reasoning
Decision Making and Problem Solving
The minimum number of D flip-flops needed to design a mod-258 counter is
option
(A) 9
(B) 8
(C) 512
(D) 258
Read Solution (Total 2)
-
- 9, 2^9=512
- 10 years agoHelpfull: Yes(2) No(1)
- 8..2^8=256
- 11 years agoHelpfull: Yes(0) No(0)
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