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Exam
A container originally contains 10 litres of pure spirit. From this container 1 litre of spirit is replaced with 1 litre of water. Subsequently, 1 litre of the mixture is again replaced with 1 litre of water and this process is repeated one more time. How much spirit is now left in the container?
option
(A) 7.58 litres
(B) 7.84 litres
(C) 7 litres
(D) 7.29 litres
Read Solution (Total 9)
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- suppose a container contains x units of liquid from which y units are taken out and replaced by water .after n operations the quantity of pure liquid =[x(1-y/x)^n]
=[10(1-1/10)^3]
=7.29 liters - 11 years agoHelpfull: Yes(4) No(0)
- 7.29 litres
- 11 years agoHelpfull: Yes(1) No(1)
- 7.29 LITRES
- 11 years agoHelpfull: Yes(1) No(1)
- 7.29 litres
10(1-1/10)^3
- 11 years agoHelpfull: Yes(1) No(0)
- spirit water
10 0
9 1
(9-9/10)=81/10 (1+9/10)= 19/10
(81/10-81/100)=7.29 19/10+81/100 =2.71 - 11 years agoHelpfull: Yes(1) No(1)
- 7.29 is the right answer.
1st round- 9L spirit and 1L are mixed then 0.9 L of spirit and 0.1 L are separate out.
2nd round 8.1 L spirit and 1.9 L water
3rd round 8.1L-0.81L=7.29L of spirit and 2.71 L water . - 11 years agoHelpfull: Yes(1) No(0)
- 7.29 liter
d=ans - 11 years agoHelpfull: Yes(0) No(0)
- yes it is 7.29litres
- 11 years agoHelpfull: Yes(0) No(0)
- D IT IS D
- 9 years agoHelpfull: Yes(0) No(0)
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