a bag contains 3 red, 5 yellow and 4 green balls. 3 balls are drawn randomly. what is the probability that the balls contain no yellow ball?

• total no of balls 12
  n(S)= 12c3=220
  3balls can be selected from 3red+4green
  =7 balls in 7c3 ways
  7c3=35
  probability 35/220=7/44
  
• 11 years agoHelpfull: Yes(33) No(3)
• probability of yellow=5*4*3/12*11*10==1/22.so no yellow=1-1/22=21/22
• 11 years agoHelpfull: Yes(13) No(0)
• the answer is 1-5c3/12c3.firt we have to pick up all the balls which are yellow and we we substract it from 1 we will get the probability of the number of balls containing no yellow ball
• 11 years agoHelpfull: Yes(10) No(3)
• ans is 7/44.
  
  total balls in the bag are:12(3R,5Y,4G)
  The total ways of selecting the 3 balls out of 12 are: 12c3
  Now the ways of selecting the balls other than yellow are:7c3
  Hence prob. is 7c3/12c3=7/44.
• 11 years agoHelpfull: Yes(4) No(0)
• total no of balls 12.
  According to the question
  Prob of getting no yellow ball=((3C3)+(4C3)+(3C2)(4C1)+(4C2)(3C1))/(12C3)
  Ans:35/220=7/44
• 11 years agoHelpfull: Yes(4) No(0)
• very sorry.Its 7/44 only. :)
• 11 years agoHelpfull: Yes(2) No(0)
• srry for last 1 it should be 7*6*5/12*11*10==7/44
• 11 years agoHelpfull: Yes(2) No(0)
• 21/55(7c3/12c3)
  
• 11 years agoHelpfull: Yes(1) No(1)
• ans is 7/44
  total probability is 12c3,required is 7c3
• 11 years agoHelpfull: Yes(1) No(1)
• 3c1+3c2*4c1+3c1*4c2+4c3/12c3
  
  =7/44
  ~0.16
• 10 years agoHelpfull: Yes(1) No(0)
• 7c3/12c3=7/44
• 7 years agoHelpfull: Yes(1) No(0)
• 13/110 ??
  
• 11 years agoHelpfull: Yes(0) No(12)