G and m can paint 720 box in 20 days ,m and h in 24 days and h and g in 15 days .g works for 4 days, m for 8 days, h for 8 days .find total no of boxes painted by them?

• g + m= 36 (720 in 20 days means 36 in 1 day)
  similarly,
  m + h= 30 and h + g= 48
  solve these 3 equations to get m=9, g=27, h=21
  now g works for 4 days , so no of boxes painted by g will be 27*4= 81
  m for 8 days so 9*8= 72
  h for 8 days so 21*8= 168
  add them all...ans is 348.
• 11 years agoHelpfull: Yes(58) No(1)
• no of boxes painted in 1 day by
  g+m=720/20=36
  m+h=720/24=30
  h+g=720/15=48
  adding these three 2(g+h+m)=114
  or g+h+m=57
  so g=27
  h=21
  m=9
  so 4*g+8*m+8*h=4*27+8*9+8*21=108+72+168=348
  total no. of boxes painted by them=348
• 11 years agoHelpfull: Yes(25) No(1)
• ans:348
  g,m and h together paint 57 boxes in 1hr
  so g paints 27 boxes in 1hr
  h 21
  nd m 9 boxes
  so total boxes required 27*4+21*8+9*8=348 boxes
• 11 years agoHelpfull: Yes(3) No(1)
• no of boxes painted in 1 day by
  g+m=720/20=36
  m+h=720/24=30
  h+g=720/15=48
  adding these three 2(g+h+m)=114
  or g+h+m=57
  so g=27
  h=21
  m=11
  so 4*g+8*m+8*h=4*27+8*11+8*21=108+88+168=364
  total no. of boxes painted by them=364
• 11 years agoHelpfull: Yes(1) No(10)
• Total number of boxes were 368
• 11 years agoHelpfull: Yes(0) No(1)