How many ways can 6084 be written as a product of two different factors?
option
a) 27
b) 26
c) 13
d) 14

• 6084 = 2^2 * 3^2 * 13^2 = so, total number of factors are (a+1)(b+1)(c+1)= 3*3*3 =27 factors. For, each two factors we can get one way to write the number as a product of two different factors.But as the two factors are to be distinct it should be (27-1)/2 = 13 ways
• 11 years agoHelpfull: Yes(70) No(7)
• 6084 =
  2^2 * 3^2 * 13^2
  now pair them up (up to the square root of 6084: 78)
  
  2*3042 =6084
  3*2028 =6084
  4*1521 =6084
  6*1014 =6084
  9*676 =6084
  12*507 =6084
  13*468 =6084
  18*338 =6084
  26*234 =6084
  36*169 =6084
  39*156 =6084
  52*117 =6084
  78*78 =6084
  Ans)c=13
• 10 years agoHelpfull: Yes(28) No(7)
• Simply factor of 6084 is = 2^2 * 3^2 * 13^2 . ------------(1)
  formula to find total factor=(a+1),(b+1),(c+1)------------(2)
  --
  Where a=2,b=2,c=2 taken power only .So put these value on given formula eq (2)
  (2+1)* (2+1)*(2+1)=3*3*3=27
  --
  So answer will be 27
• 10 years agoHelpfull: Yes(20) No(47)
• Ravi u are not right.
  u should hv calculate 1*6084=6084 so it should hv 14 ways.
  According to qstn it should hv 2 different factors so u can't count 78*78.
  Answer will be 13 ways.
• 9 years agoHelpfull: Yes(13) No(3)
• 6084 = 2^2 *3^2*13^2 total no. of factors = (a+1)*(b+1)*(c+1) where a,b,c are powers of factors so
  total no. of factors = 27.
  Now there will be repeated factors like an example
  6 has 4 factors 1,2,3,6 and when taking pairs of it we get
  1*6
  2*3
  but we can't consider the factor like 6*1 ,3*2 as they are treated as repeated.
  
  half the factors are repeated
  hence answer is 13
  
• 9 years agoHelpfull: Yes(9) No(2)
• ans=27
  6084=2*2*3*3*13*13
  so,(2+1)*(2+1)*(2+1)=27
• 11 years agoHelpfull: Yes(5) No(37)
• 27 is the answer for total no. of factors for 6084,but how to find how it can be expressed as a product of 2 factors?
  
• 11 years agoHelpfull: Yes(4) No(21)
• num = a^p*b^q*c^r
  6084=2^2*3^2*13^2
  no of factors of num = p+1*q+1*r+1
  no of factors of 6084=3*3*3=27
  how many ways is nothing but no of factors / 2 i.e,27/2=13.5 ignore the number afta decimals and here is the ans 13
• 8 years agoHelpfull: Yes(4) No(1)
• 6084=2^2*3^2*13^2
  =>3*3*3=27 factors
• 11 years agoHelpfull: Yes(3) No(22)
• 6084=2^2*3^2*13^2
  =>3*3*3=27 factors
  number of factors/2 if number of factors is even and
  (number of factors-1)/2 if number of factors is odd.
  
  Therefore: 27-1/2 = 26/2 = 13
• 7 years agoHelpfull: Yes(3) No(0)
• hju bjbjnklklkhfyvn, iugunk nkvcyufjk m, jgdggvjkb ,m hgxgfjk m, jhvy
• 8 years agoHelpfull: Yes(0) No(10)