Consider a courier company A which can deliver 100 parcels in 5 days with 5 men working for 8 hours a day. Consider another courier company B where every employee is equally effecient as that of company B. Company B is short of one man when compared to A and has a policy of asking its workers to work only for 6 hours a day. How long (in days) company B will take to deliver 100 parcels.

Options : a. 8.3 b. 24 c. 12 d 6.6

• Total amount of work done by Members of A--
  In Delivering 100 Parcels- 5x8=40x5=200 units.
  Company B has 4 employees and each of them work 6 hours a day
  Hence, Work done each day = 24 units
  Therefore no.of days required to deliver 100 parcels= No.of days required to do
  200 units of work= 200/24= 8.33. hence answer is a.
  
• 13 years agoHelpfull: Yes(9) No(1)
• work done is proportional to men,no. of days,time(of work)
  so (w/mdt) is equal in A and B cases
  here w is same in two cases
  (mdt) of A EQUALS (MDT) of B
  5*5*8=4*D*6
  implies D=8.3
• 13 years agoHelpfull: Yes(5) No(0)
• Ans: a
  When questions in which work done by two or more entities r same then the ans can be found by applying d simple formula:
  m1*d1*t1*e2=m2*d2*t2*e1
  where m1=no. of men working in A
  d1=days reqd by A
  t1=time reqd by A
  e2=efficiency of B
  n similarly for rest terms
  Put d values
  5*5*8=4*6*d2
  d2=8.3
  
• 13 years agoHelpfull: Yes(3) No(0)