Distribute 10 "different" pencils among 3 students??

• no. of ways of disributing n different things among r different person=r^n
  answer=3^10
• 11 years agoHelpfull: Yes(28) No(16)
• I think it should be..
  .we can give pencil to 1-student in 10 ways.
  2nd student in 9 ways & to 3dr studnt in 8 ways.
  so answer is 10*9*8=720
  
• 11 years agoHelpfull: Yes(27) No(2)
• #ans: 12c2 = 66
  (division of n identical item into r persons = ( n+r-1)C(r-1)
  so it will be 12c2 )
• 11 years agoHelpfull: Yes(13) No(3)
• its wrong buddy
  you can verify also , for instance
  take 3 diff. colours lets call them A,B,C i.e. n=3
  and distribute them among
  person 1 --->p1
  person 2 --->p2 , here r=2
  p1 p2
  -- --
  A B
  B A
  B C
  C B
  A C
  C A
  here we are getting only 6 ways , but a/c to you it should be 8
  i hope its clear now.
• 11 years agoHelpfull: Yes(3) No(11)
• 10*10*10=
  10^3
  
  
• 11 years agoHelpfull: Yes(3) No(2)
• ans is 3^10
• 11 years agoHelpfull: Yes(2) No(3)
• Answer verified it will be - 3^10
  use r^n for "n" diff. objects to be distributed among "r" diff. person
  
• 11 years agoHelpfull: Yes(2) No(0)
• 3^10.
  r^n,r=represents no of person and n represents no of articles then we can distribute n objecs among r differnt person in r^n ways
• 11 years agoHelpfull: Yes(2) No(0)
• 10C3*3! = 720
• 11 years agoHelpfull: Yes(2) No(0)
• I think it should be 10P3=720
• 11 years agoHelpfull: Yes(2) No(0)
• 3^10
  3*3*3*3*3*3*3*3*3*3
• 11 years agoHelpfull: Yes(1) No(4)
• 720
  as 10*9*8
• 11 years agoHelpfull: Yes(1) No(0)
• 10+3-1 C 3-1=12 C 2=66
• 11 years agoHelpfull: Yes(1) No(0)
• it should be 2^10+2^10+2^10 which is 3072 ways. this solution holds true if the any student can get any number of objects(including 0)
• 11 years agoHelpfull: Yes(0) No(0)
• if any student can receive ny number of pencils,then,one pencil can be given to any of three students..and thus,answer=3^10
• 11 years agoHelpfull: Yes(0) No(0)
• 3^10 ways ....
• 11 years agoHelpfull: Yes(0) No(0)