There is a triangle with sides 21,20 and 13. If a perpendicular is drwan in the side with length 21 from the opposite vertex, What will be the area of larger triangle the triangle is divided into?

• let the side 21 be divided into two parts- x and (21-x).
  now apply pithagoras for both sides, and equal them with the perpendicular side.
  (13)^2-x^2=(20)^2-(21-x)^2
  solving, x=5
  therefore, the area of larger side:
  0.5*16*12=96
• 11 years agoHelpfull: Yes(30) No(3)
• answer is 96
• 11 years agoHelpfull: Yes(2) No(4)
• the perpendicualar on opposite sides devides in ratio of 2:1
  2x+x=21 of x=7
  larger traingle side =2*7=14
  p=sqrt(20^2-14^2)=14.28
  area of larger traingle=1/2*14.28*14=99.96 or 100
• 11 years agoHelpfull: Yes(0) No(5)
• The area of the bigger half is 96 !!!
• 11 years agoHelpfull: Yes(0) No(0)
• bhai pehle email ke liye padho...
• 11 years agoHelpfull: Yes(0) No(0)
• perpendicular divides side 21 into x and 21-x
  by pgt
  13^2-x^2=20^2-(21-x)^2
  x=5
  area of larger side
  0.5*16*21=168
• 7 years agoHelpfull: Yes(0) No(0)