1!+2!+3!+4!+5!+...................+68! WHAT IS THE DIGIT AT TENTH PLACE

• 10! to 68!, each term has last two digit=00
  now 1!+2!+3!+4!+5!+...+10!=1+2+6+24+120+720+..40+...20+....80
  = 13(last two digit of sum)
  hence last two digit of 1!+2!+3!+4!+5!+...................+68!=00+13=13
  hence DIGIT AT TENTH PLACE =1
• 11 years agoHelpfull: Yes(42) No(0)
• ans:1
  all factorial from 10 onwards will have atleast 2 0's at the end. hence all nos from 1! to 9! will have some value in the tenth's place.
  hence we add 1!+2!+3!+4!+5!+6!+7!+8!+9!=409113
  hence tenth place is 1
• 11 years agoHelpfull: Yes(7) No(1)
• 10! to 68!, each term has last two digit=00
  now 1!+2!+3!+4!+5!+...+9!=1+2+6+24+120+720+..40+...20+....80
  = 13(last two digit of sum)
  hence last two digit of 1!+2!+3!+4!+5!+...................+68!=00+13=13
  hence DIGIT AT TENTH PLACE =1
• 11 years agoHelpfull: Yes(3) No(2)
• 1!+2!+3!+4!=31
  5!+6!+7!+8!+9!+10!+......+68!=.....80
  so 10th place = 80+31=111
  ans = 1
• 11 years agoHelpfull: Yes(2) No(15)
• is that digit at tens place or tenth place?
  
• 11 years agoHelpfull: Yes(2) No(1)
• 1
• 11 years agoHelpfull: Yes(0) No(1)