x+y+z=15

xy+yz+zx=75

then

x+4y+z/3z=?

• Ans 2
  suppose x=5,y=5 and Z=5
  so x+y+z=15;
  xy+yz+zx=75
  so x+4y+z/3z=5+4*5+5/3*5=5+20+5/15=30/15=2
• 11 years agoHelpfull: Yes(9) No(4)
• x=5,y=5 and Z=5
  so x+y+z=15;
  xy+yz+zx=75
  so x+4y+z/3z=5+4*5+5/3*5=5+20+5/15=30/15=2
  
• 10 years agoHelpfull: Yes(1) No(1)
• both above two equestion will be satisfied only when
  x=5, y=5, z=5
  so, value of (x+4y+z)/3z=(30/15)=2
  thus ans=2
• 10 years agoHelpfull: Yes(0) No(0)