In certain city the Taxi charges comprise of a fixed charge and the charge of the distance travelled. A person paid ` 156 for a journey of 16 km and another person paid 204 for the journey of 24 km. The amount paid by a passenger who has travelled 30 km is

• let the fixed charge = RS x
  per km cost = RS y
  according to question
  x+16y=156
  x+24y=204
  solving we get x RS 60 and y= RS 6
  so to 30 km= 60+(30*6)
  =RS 24o
• 11 years agoHelpfull: Yes(4) No(0)
• for 16 =1^2-6=5 as middle digit so 156
  for 24= 2^2-4=0 as mid digit 204
  for 30=3^2-0=9 AS MID digit=390
• 11 years agoHelpfull: Yes(1) No(2)
• let A is the fixed charge and B is charge for per km
  A+16B=156....................(1)
  A+24B=204..........................(2)
  A=60, B=6
  FOR 30 KM TRAVEL 60+(30*6)=240
  
• 11 years agoHelpfull: Yes(0) No(0)