ABC is an isosceles right angled triangle with angle B = 90°. On the sides AC and AB, two equilateral triangles ACD and ABE have been constructed. The ratio of areas of triangle ABE and triangle ACD is

• let equal side of iso trian be x
  ac = sqt2*x (hypotenous)
  area of abc = sqt3/4*2*x^2
  area of abe = sqt3/4*x^2
  so area of abe/abc = 1:2
• 11 years agoHelpfull: Yes(3) No(1)
• the ratio of traingles ABE and ACD is 1:1
  
• 11 years agoHelpfull: Yes(0) No(3)