A can do a work in 10 days B can do it 12 days C can do it in 15

let "X" days taken by A to comlete work,
X-3 days by c
2 days by B
so together x/10+2/12+x-3/15=1
x=62/10 =6(1/5)
10 years agoHelpfull: Yes(13) No(0)

6(1/5)days
10 years agoHelpfull: Yes(10) No(1)
a's 1 day work=10%
B's 1 day work=8.33%
C's 1 day work=6.66%
Total work done by them in 1 day=25%
in 2 days they can complete 50% of the work.
on 3rd day b and c work alone, so work=16.66%
last 3 days A works alone=3*10=30% of the work
so c leaves after doing 70% of the work.
hence total time taken= 2+1.2+3=6.2 days
10 years agoHelpfull: Yes(4) No(0)
The answer is 6(1/5) days.
10 years agoHelpfull: Yes(3) No(1)
A's 1 day's work=1/10
B's 1 day's work=1/12
c's 1 day's work=1/15
(A,B,C)'s 1 day work=1/10+1/12+1/15=1/4
they can finish work in 4 days
(A/Q)- B work for 2 days&C work for 1 day and rest work done by A himself
so A B C work for 1 day together=1/4 part
A&B work for 2nd day=1/10+1/12=11/60part
work done upto 2 days=11/60+1/4=13/30part
rest work left=1-13/30=17/30
for A to do the work it takes 17/30*10=17/3 days to complete
total no of days=2+17/3=23/3 days (ans....)=23/3 days
10 years agoHelpfull: Yes(2) No(9)
let A completes the work in "x" days i.e the total no days required,
then B works for (x-2)days and C works for (x-3)days
hence (A's works for(x/10)+B's works for(x-2)/12+c's work for (x-3)/15 )=1
so, x=82/15 Ans....
10 years agoHelpfull: Yes(1) No(0)
ans:7 days by using chocolate method.
10 years agoHelpfull: Yes(1) No(0)
5 to 6 days..
10 years agoHelpfull: Yes(0) No(0)

A can do a work in 10 days, B can do it 12 days,C can do it in 15 days, they started the work together after 2 days B left, and C left 3 days before the the work finished. how many days it take to finish the work?