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Winning probability of three horses out of 18 horses are given i.e.1/8,1/6,1/7.What is the probability one of the horses will win?
Read Solution (Total 8)
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- p(winning)=1-P(all three losses the match)
1-7/8*5/6*6/7=3/8
ans p(win)=3/8 - 11 years agoHelpfull: Yes(29) No(8)
- ans::: p(h1)+p(h2)+p(h3)
1/8+1/6+1/7=73/168 - 11 years agoHelpfull: Yes(14) No(5)
- probability of winning of one of the horses= 1/8 + 1/6 + 1/7= 73/168
- 11 years agoHelpfull: Yes(7) No(0)
- 1/8+1/6+1/7=73/168
- 11 years agoHelpfull: Yes(5) No(0)
- (1/8*7/8)+(1/6*5/6)+(1/7*6/7)/18c3
- 11 years agoHelpfull: Yes(1) No(1)
- additive probability !!!
73/168. - 11 years agoHelpfull: Yes(0) No(0)
- pls explain in detail
- 11 years agoHelpfull: Yes(0) No(0)
- probability to win anyone of the horse means out of three horses anyone can win i.e., horse1 or(+) horse2 or(+) horse3=1/8 + 1/7 + 1/6 = 73/168
- 11 years agoHelpfull: Yes(0) No(0)
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