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N no of dice are thrown the probability of getting a sum of 40 before 56 is 2/7 then what may be the value of N
option
A. 21
B. 22
C. 24
D. cant determine
Read Solution (Total 5)
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- since the denominator in the throw of dice= sample space=6^N thus 6^N=multiple of 7 thus ans = 21
- 11 years agoHelpfull: Yes(13) No(4)
- 6^N is not multiple of 7.... isnt it? samarth...
- 11 years agoHelpfull: Yes(6) No(0)
- Please explain
- 11 years agoHelpfull: Yes(2) No(1)
- please write the solution
- 11 years agoHelpfull: Yes(1) No(0)
- 40 = 3*9+1*13
9 die should come up with 3, and 13 die should come up with 1.
therefore, N=9+13=22. - 11 years agoHelpfull: Yes(0) No(0)
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