(61-a)(61-b)(61-c)(61-d)(61-e)=425.Find a+b+c+d+e.This was one of my starred questions.

• ans is 276
  
  425 on factorising gives 17*5*5
  these factos can also be written as 17*5*5*1*1
  which can be further be written as (61-44)(61-56)(61-56)(61-60)(61-60)
  
  this gives value of a=44, b=56, c=56, d=60, e=60
  hence sum of a+b+c+d+e= 44+56+56+60+60= 276
• 11 years agoHelpfull: Yes(85) No(2)
• 276
  
  44+56+56+60+60
• 11 years agoHelpfull: Yes(10) No(4)
• if a,b,c,d,e are in increasing order and are distinct then
  (61-66)*(61-62)*(61-60)*(61-56)*(61-44)=425
  hence a,b,c,d and e are 66,62,60,56 and 44 respectively
  so a+b+c+d+e=288...
• 11 years agoHelpfull: Yes(9) No(3)
• 425 on factorising gives 17*5*5
  these factos can also be written as 17*5*5*1*1
  which can be further be written as (61-44)(61-56)(61-56)(61-60)(61-60)
  
  this gives value of a=44, b=56, c=56, d=60, e=60
  hence sum of a+b+c+d+e= 44+56+56+60+60= 276
• 11 years agoHelpfull: Yes(2) No(0)
• 44+56+56+60+60=289
• 11 years agoHelpfull: Yes(1) No(8)
• 276.................
• 11 years agoHelpfull: Yes(1) No(0)
• Since we don't have any condition on a, b, c, d & e; both 276 & 288 are correct.
• 11 years agoHelpfull: Yes(1) No(0)
• plz explain...
• 11 years agoHelpfull: Yes(0) No(2)
• Ans is 276
  
• 11 years agoHelpfull: Yes(0) No(0)
• I think Shuvadip Lahiri is correct but y we have to take minus values for 1st and last factors please explain if u know the reason
• 11 years agoHelpfull: Yes(0) No(0)