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35674 term in 12345678910111213.... ? What is the 56743rd term in the series?

Read Solution (Total 6)

1 to 9=9 no.s 1 digit each no.
9 to 99=90no.s 2 digit each,total digit=90*2=180 terms
99 to 999=900 no.s 3 digit each,total digit=900*3=2700
999 to 9999=9000 no.s 4 digit each,total digit=9000*4=36,000
now till 999,we have=9+180+2700=2889 digits
till 9999 we hv=2889+36000=38889 digits
56743-38889=17854
after 9999 each no. has 5 digit
so 17584/5=3570 with remainder 4.
3570th no after 9999 =9999+3570=13569
next term=13570...4th digit=7 ..so ans=7
11 years agoHelpfull: Yes(27) No(4)

lund hai tu @Pradeep
11 years agoHelpfull: Yes(24) No(0)
I think its a Incomplete ques.
11 years agoHelpfull: Yes(2) No(4)
56743 because it is an AP series where 1st term is 1 and d=1.
11 years agoHelpfull: Yes(1) No(9)
56743 because it is an AP series where 1st term is 1 and d=1.
11 years agoHelpfull: Yes(1) No(6)
It is in AP
Bcz 1,2,3,...........56743
where a=1,d=1, and Total Terms in Series is 56743
By Using This Info We can Calculate the Tn Term i.e :: tn=a+(n-1)d
U can Get 56743
10 years agoHelpfull: Yes(1) No(1)

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