4*^3+5*^3+5*4 is divide by x-9.what is value of x and what is remainder.

• 
  4^3+5^3+5*4=64+125+20=209
  209%11=0
  x-9=11
  x=20
  209%20=9
• 11 years agoHelpfull: Yes(20) No(3)
• the ques should be what is the value of x if reminder is ......
  i think ques wrong
• 11 years agoHelpfull: Yes(8) No(2)
• 4^3+5^3+5*4=64+125+20=209
  209=19*11
  so there are two cases:
  1)x-9=11
  here x=20;
  2)x-9=19
  here x=28;
• 11 years agoHelpfull: Yes(4) No(0)
• 4^3+5^3+5*4=64+125+20=212/x-9
  so x=11 so reminder will be 0
  or x=12 so reminder will be 2
• 11 years agoHelpfull: Yes(1) No(17)
• 64+125+625 = 814
  which is divisible by 2,.......,814
  so min. value of x = 11.
  max. value of x = 823.
• 11 years agoHelpfull: Yes(1) No(6)
• the following ansrs are wrong...
  
• 11 years agoHelpfull: Yes(1) No(2)
• i want ARUN GUPTA to provide us with the correct question...
• 11 years agoHelpfull: Yes(1) No(0)