how many vehicle registration number plates can be formed with digits 1,2,3,4,5(no digits are repeated),if its given that the registration number can have 1-5 digits.

• You can have registration plates of 5,4,3,2 or 1 digits
  So, it's 5*4*3*2*1 + 5*4*3*2 + 5*4*3 +5*4 + 5
  =120 + 120 + 60 + 20 +5
  = 325 ans.
• 10 years agoHelpfull: Yes(43) No(2)
• case 1: the vehicle reg. no has 1 digit
  5 such plates possible.
  case 2: the vehicle reg. no has 2 digits
  5P2 = 20 such plates possible.
  case 3: the vehicle reg. no has 3 digits
  5P3 = 60 such plates possible.
  case 4: the vehicle reg. no has 4 digits
  5P4 = 120 such plates possible.
  case 5: the vehicle reg. no has 5 digits
  5P5 = 120 such plates possible.
  therefore total plates possible = 5+20+60+120+120= 325
• 10 years agoHelpfull: Yes(27) No(0)
• ans is 325...
• 10 years agoHelpfull: Yes(4) No(0)
• factorial of 5
• 10 years agoHelpfull: Yes(3) No(7)
• there are 5 digits
  for 5 digit num plate =5*4*3*2*1
  for 4 digit num plate=5*4*3*2
  for 3 digit =5*4*3
  for 2 digit=5*4
  for 1 digit=5
  adding all=325 is total num of plates can be formed
  
• 10 years agoHelpfull: Yes(2) No(0)
• You can have registration plates of 5,4,3,2 or 1 digits
  So,in last digit , we have 5 possibilities .so already one number got over.rest 4 numbers are available in last place and in second place , we have 5*4 as already one digit got filled in last place
  ...and after filling in the same manner we get :the following
  it's 5*4*3*2*1 + 5*4*3*2 + 5*4*3 +5*4 + 5
  =120 + 120 + 60 + 20 +5
  = 325 ans
• 10 years agoHelpfull: Yes(1) No(0)
• 3125
  5c2*5^4
• 10 years agoHelpfull: Yes(0) No(8)
• =5!+5(4!)+4(3!)+3(2!)+2(1!)+1(1!)
  =120+120+24+6+2+1
  =253
• 10 years agoHelpfull: Yes(0) No(8)