What is the probability of getting 53 sundays in a leap year???

• A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days.
  
  The remaining 2 days may be any of the following :
  
  (i) Sunday and Monday
  
  (ii) Monday and Tuesday
  
  (iii) Tuesday and Wednesday
  
  (iv) Wednesday and Thursday
  
  (v) Thursday and Friday
  
  (vi) Friday and Saturday
  
  (vii) Saturday and Sunday
  
  For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday.
  
  n(S) = 7
  
  n(E) = 2
  
  P(E) = n(E) / n(S) = 2 / 7
• 10 years agoHelpfull: Yes(41) No(0)
• 366/7=52 weeks and 2 days
  n(E)=2
  n(S)=7
  so p=n(E)/n(s)=2/7
• 10 years agoHelpfull: Yes(9) No(0)
• probablity of getting 1 sunday out of 7 days is 1/7.
  And in leap year 1 more day could be any btwn mon-sun..
  so it is= 2/7..
  hence extra day(366th) could be sunday
• 10 years agoHelpfull: Yes(2) No(0)
• IN LEAP YEARS=366 DAYS
  i.e 53weeks+2days
  so getting 2days sunday in a weeks is=2/7
• 10 years agoHelpfull: Yes(2) No(0)
• 2/7 is ans
  
• 10 years agoHelpfull: Yes(1) No(0)
• 2/7, 52 sundays, extra 2 days.
  so, P(E)=2/7
  
• 10 years agoHelpfull: Yes(1) No(0)
• a leap yr has 366 days i.e. 52*7 + 2 days. 52 weeks has 52 Sundays.Now the probability of getting another Sunday from remaining 2 days is 2/7.
• 10 years agoHelpfull: Yes(1) No(0)
• in a leap year =366 days means 52 weeks and 2 days
  2 day will be... sun & mon, mon & tues, tues & wed, Wed & thurs, thurs & fri, fri & sat, sat & sunday
  so probability of 2 sunday = 2/7
• 10 years agoHelpfull: Yes(1) No(1)
• 2/7 hahahha
• 10 years agoHelpfull: Yes(0) No(2)
• (sun,mon),(mon,tue),(tue,wed),(wed,thur),(thur,fri),(fri,sat),(sat,sun);
  p=2/7.
• 10 years agoHelpfull: Yes(0) No(0)
• 52 weeks+ 2 other day in total of 366 days
  so its 2 out of 7 days
  so its 2/7
• 10 years agoHelpfull: Yes(0) No(0)