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there are 4 boxes of red,yellow,green,blue.if 2 boxes are selected then find the probability of getting at least one green or red box.
Read Solution (Total 7)
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- P(atleast 1 green or red)=1-P(no red or green)
=1-(8/16)*(7/15) /*no replacement
=23/30
ans 23/30 - 11 years agoHelpfull: Yes(6) No(1)
- i think 5/6 is d ans
as thr r total 6 possibilities
and thr is only 1 possibility for not hving atleast 1 green or 1 red box - 11 years agoHelpfull: Yes(3) No(0)
- Among two boxes, in one box R or G is to be placed so,2C1 and in remaining one box can be
filled in 3C1 ways so ,total is
2C1+3C1=5
- 10 years agoHelpfull: Yes(1) No(0)
- ans is 1/2
because
here 4 boxes
each having probability 1/4.....(1/4+1/4+1/4+1/4=1)
then probability of getting either green or red box is (1/4)+(1/4)
hence 1/2 is the answer - 10 years agoHelpfull: Yes(1) No(0)
- answer is (4c1*3c1)/4!
- 11 years agoHelpfull: Yes(0) No(1)
- n(S)=4c2=6
n(E)=4c1+3c1=7
p(E)=7/6 ans - 11 years agoHelpfull: Yes(0) No(3)
- @rakesh...7/6 can not be answr...it is >1 and probability of anythng alws >0 but
- 11 years agoHelpfull: Yes(0) No(0)
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