there are 4 boxes of red,yellow,green,blue.if 2 boxes are selected then find the probability of getting at least one green or red box.

• P(atleast 1 green or red)=1-P(no red or green)
  =1-(8/16)*(7/15) /*no replacement
  =23/30
  ans 23/30
• 11 years agoHelpfull: Yes(6) No(1)
• i think 5/6 is d ans
  as thr r total 6 possibilities
  and thr is only 1 possibility for not hving atleast 1 green or 1 red box
• 11 years agoHelpfull: Yes(3) No(0)
• Among two boxes, in one box R or G is to be placed so,2C1 and in remaining one box can be
  filled in 3C1 ways so ,total is
  2C1+3C1=5
  
• 11 years agoHelpfull: Yes(1) No(0)
• ans is 1/2
  
  because
  here 4 boxes
  each having probability 1/4.....(1/4+1/4+1/4+1/4=1)
  then probability of getting either green or red box is (1/4)+(1/4)
  hence 1/2 is the answer
• 11 years agoHelpfull: Yes(1) No(0)
• answer is (4c1*3c1)/4!
• 11 years agoHelpfull: Yes(0) No(1)
• n(S)=4c2=6
  n(E)=4c1+3c1=7
  p(E)=7/6 ans
• 11 years agoHelpfull: Yes(0) No(3)
• @rakesh...7/6 can not be answr...it is >1 and probability of anythng alws >0 but
• 11 years agoHelpfull: Yes(0) No(0)