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!1+!2+!3+...........+!50?.
Read Solution (Total 6)
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- ans: 50!(51)/50
Write eq as:
50!+49!+48!+...1!
50!(1+1/50+1/50*49....)
50!(1+1/50)... since other terms will be neglegible
50!(51)/50 - 11 years agoHelpfull: Yes(32) No(3)
- for these type of exprsn formula z (n+1)!/n
so ans= 51!/50.
- 11 years agoHelpfull: Yes(14) No(3)
- 50!(!1/!50+!2/!50+!3/!50+......+!49/!50+!50/!50)
= !50(0+0+0+.......0+0+1/50+1)
= !50(1+1/50)
= !50*51/50
- 11 years agoHelpfull: Yes(7) No(2)
- I think the options also play an important role and if they have values instead of factorial notation than best way to go about it is to find unit digit. Its very simple since we just have to calculate till 4!; reason is that from 5! onward each term will have a zero at its unit place. 1 + 2 + 6 + 4 + 0 + ..... + 0 = 3.
- 11 years agoHelpfull: Yes(2) No(2)
- It can be solved by : (n+1)!/n
so here answer will be : (50+1)!/50 = 51!/50.
If any query you can ask - 11 years agoHelpfull: Yes(2) No(0)
- [{50*(50+1)}/2]!=25*51!=1275!
- 11 years agoHelpfull: Yes(0) No(0)
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