bag has 1,3,5,7,9,11 and 13 cm sticks .find the probablity that they they will form a triangle if 3 sticks are drawn?

• Ans is 13/35
  Total way of selecting=7C3=35
  Now selections that are in fever=(3,5,7),(3,7,9),(3,9,11),(3,11,13),(5,7,9),(5,7,11),(5,9,11),(5,9,13),(5,11,13),(7,9,11),(7,9,13),(7,11,13),(9,11,13)=total 13.
  Others are rejected because to form a triangle it is neccessary that the sum of 2 small sides must be greater than the third greatest side
• 10 years agoHelpfull: Yes(29) No(3)
• sry 4 the mistake guyz .... the sample space = 7c3 =35 & favourable events= 13
  so probability= 13/35
• 10 years agoHelpfull: Yes(4) No(3)
• Events={ (3,5,7),(3,7,9),(5,7,9),(9,3,11),(5,7,11),(9,5,11),(11,9,13),(11,7,13),(11,5,13),(11,3,13),(9,7,13),(9,5,13) } =12
  Sample space = 6c3=20
  Probability = 12/20
  =3/5 (ans)
• 10 years agoHelpfull: Yes(1) No(3)
• 12/6c3
  = 12/20
  = 3/5
• 10 years agoHelpfull: Yes(0) No(4)
• events=8
  sample space=20
  p=2/5
  
• 10 years agoHelpfull: Yes(0) No(4)