Elitmus Exam

(999^x-999^y)where x>y>0 fin remainder when divided by 1000.

Read Solution (Total 3)

The possible Remainders are 2 and 998 depending on value of x and y.

the actual question is like this how many remainders are possible when (999^x-999^y)where x>y>0 is divided by 1000, consider 0 also as reainder.... and answer for this question is 3.
10 years agoHelpfull: Yes(5) No(8)

3 would be the ans...
10 years agoHelpfull: Yes(1) No(0)
there are three possibilities remainder are 0,2,998 and this cycle will repeat..........
10 years agoHelpfull: Yes(1) No(0)

Elitmus Other Question

There is a circular track of length 440m. There are 3 persons A, B and C standing at different points on the track ready to start the race.A an B are standing diametrically opposite to each other while C is exactly midway between A an B, such that A, B and C are standing in clockwise order. The race started at 10 am. The speeds of A,B and C are respectively 5m/s,10m/s and 8m/s. at what time would B and C meet for the second time,if all the three of them run in the clockwise direction.
option
a) 10:06:25 am
b) 10:04:35 am
c) 10:00:50 am
d) none of these. 4 childrens born in consective years,every year her mother calcilates the product of their ages,what is always true for that product:
a) prime no. + 1
b)square of a number -1
c) always divied by 10