Elitmus
Exam
(999^x-999^y)where x>y>0 fin remainder when divided by 1000.
Read Solution (Total 3)
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- The possible Remainders are 2 and 998 depending on value of x and y.
the actual question is like this how many remainders are possible when (999^x-999^y)where x>y>0 is divided by 1000, consider 0 also as reainder.... and answer for this question is 3. - 11 years agoHelpfull: Yes(5) No(8)
- 3 would be the ans...
- 11 years agoHelpfull: Yes(1) No(0)
- there are three possibilities remainder are 0,2,998 and this cycle will repeat..........
- 11 years agoHelpfull: Yes(1) No(0)
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