Elitmus
Exam
Logical Reasoning
Cryptography
H O P
* D U S
-------
P T P O
H O P
P P E P
-----------
P H S T S O
Read Solution (Total 11)
-
- H O P
* D U S
-------
U T P O
H O P
P P E P
-----------
P H S T S O - 11 years agoHelpfull: Yes(4) No(0)
- HOP
DUS
------
UTPO
HOP
PPEP
--------
PHSTSO
SOLUTION:
382
614
------
1528
382
2292
---------
234548
explanation:
1. try to find 1 & o
here in the 2nd row we can clearly see
U*HOP= HOP
hence we can say U=1
2.check the unit multiplication i;e:
S*P=O
U*P=P
D*P=P
here U*P & D*P gives the same result i;e: P
so we can take D=6
so the expected value for P could be{2, 4, 8}
3.now check through the additions:
column 2 from left: P+carry = H
so the expected value for H could be{3, 5, 9}
as in this case carry must be 1
and also one more addition with P is given i;e, P+P=S
so we can predict value for S also {4, 8, 6}
now one more addition:
3rd column from the left:
U+H+E+Carry= S+ Carry,
now check with all the expected value we found
E=9, H=3, P=2 & S=4
and the problem solved.:) - 11 years agoHelpfull: Yes(4) No(1)
- 382
*614
-----------
1528
382
2292
-------------
234548 - 11 years agoHelpfull: Yes(2) No(4)
- quetions were:- a) value of o? ans-8
b)sum of O+P+S+D? ans-20
c)which of the following num doesnot appear in the solution?
obtions : 9,7,8,all of these ans-7 - 11 years agoHelpfull: Yes(2) No(0)
- i think question is wrong,because p=2,but in first product we get p=1 after multip, so either p=2 is wrong or p should not be there in first product,insted we can write r.
- 11 years agoHelpfull: Yes(2) No(0)
- trick is practice of 20-30 questions of cryptaritmatic. There is no other way around it.Solve all the questions here http://cryptarithmetic.wordpress.com/ you'll be able to solve every question of cryptaritmatic. Waise bhi this must be most chindi question in elitmus history
- 11 years agoHelpfull: Yes(1) No(0)
- WOT IZ THE BASIS OF NUMBERING THE LETTERS...??? I MEAN HOW DO V FIND OUT THAT H=3, O=8,P=2,
etc....??? wot z the trick...???? - 11 years agoHelpfull: Yes(0) No(0)
- as far as logic goes,
hop*u=hop (So u must be 1 here)
hop*d=ppep(here p*d results in p so it can be only 1,5,6 but 1 cannot be value so only 5,6)
in addition of (p,h,e) carry over goes to p carry over can only be (1 or 2)i.e whatever the value of p is h is greater than that by 1 or 2
now put the value of d as 6 then p can be (2,4,8) just put the value of p as 2 and h as 3 multiplication gets solved instantly - 11 years agoHelpfull: Yes(0) No(0)
- in question S & O are swapped, for the solving it doesn't make difference, but when answering, what is the value of O, then it does.
- 11 years agoHelpfull: Yes(0) No(0)
- U in place of P...sorry ... after all human brain... :)
- 11 years agoHelpfull: Yes(0) No(0)
- wrong question
- 9 years agoHelpfull: Yes(0) No(0)
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