What is the maximum remainder when (104)^n is divided with 51

• since 104/51=2, hence 2^n can give max 50, (as no. is divided by 51 so max remainder can be 50), thus 2^5=32 is max what we get
• 11 years agoHelpfull: Yes(28) No(2)
• (2)^n
  remainder=32
• 11 years agoHelpfull: Yes(13) No(1)
• if
  N value Reminder
  1 104/51 2
  2 104*104/51*51 2*2
  3 104*104*104/51*51*51 2*2*2
  4 104*104*104*104/51*51*51*51 2*2*2*2
  5 104*104*104*104*104/51*51*51*51*51 2*2*2*2*2
  6 104*104*104*104*104*104/51*51*51*51*51*51 2*2*2*2*2*2=64 further divisible by 51 reminder is 13
  
  so maximum possible reminder is : 32
  
  Thank you
• 11 years agoHelpfull: Yes(6) No(0)
• ans is 32.-maximum
• 11 years agoHelpfull: Yes(2) No(1)
• 104%51= 2.
  
  so we have 2^n /9
  the max no that 9 leaves as remainder is 8.
  so ans =8.
• 11 years agoHelpfull: Yes(0) No(6)
• How 32?Please explain
  
• 11 years agoHelpfull: Yes(0) No(0)
• For maximum firstly we will find the value of n we can find it by 51=3×17 so we will get maximum value [104/17] or [104/3]+[104/3^2] and so on and we will get n=6 so 104^6/51=2^6/51=64/51=13(ans)
• 10 years agoHelpfull: Yes(0) No(2)
• Maximum Reminder is 32 and minimum remainder is 1
• 9 years agoHelpfull: Yes(0) No(0)
• 32 would be the answers
• 7 years agoHelpfull: Yes(0) No(0)