Elitmus
Exam
Numerical Ability
LCM and HCF
A number when divided by 10, 15, 22 leaves remainder 4, 9, 10. What is the middle two numbers of that number. eg from
abcd, what is bc?
Read Solution (Total 9)
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- answer is 95. 10A+4=15B+9=>30D+24 =22C+10=>330E+54
4 digit greatest number of this form will be 9954. - 11 years agoHelpfull: Yes(11) No(6)
- N=10*a+4
N=15*b+9
N=22*c+10
let take higest factor and check whether it divides by 10 and leaves remainder 4 .we will get 54 so
lcm(10,15,22)+54=9900+54=9954, abcd=9954 so bc is 95
- 10 years agoHelpfull: Yes(8) No(0)
- ans 89
number is 4894 - 11 years agoHelpfull: Yes(4) No(7)
8 and 9
- 11 years agoHelpfull: Yes(1) No(5)
- sorry the actual question was What is the greatest 4 digit number...
- 11 years agoHelpfull: Yes(0) No(5)
- It is 54 itself. two digit number.Then why search 4 digit number.
54 divided by 10. remainder is 4
54 divided by 15. remainder is 9
54 divided by 22. remainder is 10
- 11 years agoHelpfull: Yes(0) No(6)
- result is 4894 = 89.
- 10 years agoHelpfull: Yes(0) No(1)
- here there might be possible to be true of various ans.so without option can not say properly.if u have options then through option and taking l.c.m of these three number u wil be in situation to find the solution
- 10 years agoHelpfull: Yes(0) No(0)
- 10 * 15 * 22
+ + + = 10+22*15+9*10+4=4894 so..89 is the answer
4 9 10 - 9 years agoHelpfull: Yes(0) No(0)
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