find the number of digits in the product of (5^82*32^16)

• 5^82*32^16=5^82*2^80
  =5^2*(5^80*2^80)
  =25* 10^80
  no. of digit in product=2+80=82
• 11 years agoHelpfull: Yes(46) No(1)
• ans is 82.
  5^80*5^2*2^80.so 80 number of zeros plus two more digits i.e 25
• 11 years agoHelpfull: Yes(11) No(0)
• take log of above given expression will give no of digits. ans= 82
• 11 years agoHelpfull: Yes(6) No(0)
• ans is 82.
  5^80*5^2*2^80.so 80 number of zeros plus two more digits i.e 25
  
• 11 years agoHelpfull: Yes(1) No(0)
• 5^82*32^16
  we can write 5^2*5^80*(2)^(5*16)
  => 25*5^80*2^80
  => 25*10^80
  here no of Zero is 80 except 1 so with one no of digits in 10^80 is 1+80=81
  and also 25 contain 2 digits..
  so, 81+2=83 asn...
• 10 years agoHelpfull: Yes(1) No(4)
• can any one tell why should we add +2?
• 9 years agoHelpfull: Yes(0) No(0)
• Karam tarun as the no we get by solving is 250000000 up to 80 times 0 . so total digits for 25 I.e 2 digit and for 80 times 0 I.e 80 so 80+2 =82
• 9 years agoHelpfull: Yes(0) No(0)