A works in 10 days to complete the task,B works in 12 days,C works in 15 days, if A leaves after 2 days,B leaves after 3 days. How many days are required to complete the task ?

• A(2 days work)+ B(3 days work)+ c(x days work)=1(total work done is always equal to 1)
  2/10 + 3/12 + x/15 = 1
  x = 8.25
• 11 years agoHelpfull: Yes(22) No(2)
• a+b+c 2 day work = 2(1/10 + 1/12 + 1/15) = 1/2
  b+ c 1 day work = (1/12 + 1/15) = 3/20
  work left = 1 - (1/2 + 3/20)
  = 1 - 13/20
  = 7/20
  now this work will be finished by c alone = 15* (7/20) days
  = 5.25 means 5 days 6 hrs
• 11 years agoHelpfull: Yes(11) No(6)
• let the work be making 60 problems, A can do it 6 a day, B 5 a day and D 4 a day.
  A+ B+C in two days completes 30 problems.
  B+C in the next day completes 9 problems
  
  C can complete the remaining work in 21/4 days 5.25 days
  Total days = 2+1+5.25 = 8.25
• 11 years agoHelpfull: Yes(8) No(4)
• A does W in 10 days
  B W in 12 while C in 15 days so there respective rates are W/10,W/12 and W/15.
  as A for 2 days so w/10*2 + w/12*3 + w/15*n = w
  So find n i.e. 8.25 days so C has to do work for 8.25 days.
• 11 years agoHelpfull: Yes(4) No(0)
• total time taken to finish the work = 5.25 + 3 = 8.25 days
• 11 years agoHelpfull: Yes(3) No(0)