IBM
Company
Logical Reasoning
Number Series
0,1,1,1,1,2,1,3,3,2,1,?
Read Solution (Total 15)
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- First make pairs of 2 digit from left to right:
01,11,12,13,32,1?. now their the some of these pairs are:
0+1=1
1+1=2
1+2=3
1+3=4
3+2=5
1+?=6 >>> hence the answer is 5.
Hope you got it. :) - 11 years agoHelpfull: Yes(167) No(9)
- 0,1,1,1,1,2,1,3,3,2,1
Step I: (0,1,1,1),(1,2,1,3),(3,2,1,?)
Step II:(0*1+1=1),(1*2+1=3),(3*2+1="7")
Hence the ans is 7. - 11 years agoHelpfull: Yes(17) No(10)
- group of 4
1*1+0=1(4th term)
1*2+1=3(8th term)
1*2+3=5(ans) - 11 years agoHelpfull: Yes(12) No(4)
- the sum of conscutv 2 no.s are like 1,2,3,4,5 so nxt sum ll b 6.so the ans is 5
- 11 years agoHelpfull: Yes(7) No(1)
- (0+1)*1=1, (1+2)*1=3 ,(3+2)*1=5.....
ans is 5 - 11 years agoHelpfull: Yes(7) No(1)
- please tell me which one is correct answer.I am really very confused.....
- 11 years agoHelpfull: Yes(5) No(2)
- (0,1,1),(1,1,2),(1,3,3),(2,1,?)
consider 3rd term in every block (1,2,3,?)
so ans=4 - 11 years agoHelpfull: Yes(3) No(16)
- 0+1+1=2
1+1+2=4
1+3+3=7
2+1+8=11
ans=8 - 11 years agoHelpfull: Yes(3) No(2)
- I hv a request kindly express ur experienc and question, asked in ibm if u hv attended...my email id-rahul123rkg@gmail.com (its RAHUL "L" IN my email id)
- 11 years agoHelpfull: Yes(2) No(5)
- (0,1,1,1)(1,2,1,3)(3,2,1,?)
add of 1st 3
add of 2nd 7 : so increased by 4
so if 3rd one incresed by 4 it will be 11.to get 11 :11-(3+2+1)=11-6=5
so the answer is 5. - 11 years agoHelpfull: Yes(1) No(2)
- 5
successive 1,1,1,1,
and 3,3
so the nxt will be only 5 - 11 years agoHelpfull: Yes(1) No(1)
- 0+1+1+1+1=4 4%2=2
1+3+3+2+1=10 10%2=5
so ans is 5 - 10 years agoHelpfull: Yes(1) No(0)
- ANSWER: 8
0,1,1,1,1,2,1,3,3,2,1,?
Three to 1 block -->(0,1,1),(1,1,2),(1,3,3),(2,1,?)
(0+1+1=2),(1+1+2=4),(1+3+3=7),(2+1+?=?)
2,4,7,should be follow by 11
(2+1+?=11)
then ? = 11-3=8
So answer is 8 - 11 years agoHelpfull: Yes(0) No(10)
- 8 is my answer
take three number sum
(0+1+1)=2
(1+1+2)=4
(1+3+3)=7
(2+1+x)=11 ,so hhere diff bw sum are 2,3,4 so ans 8 - 11 years agoHelpfull: Yes(0) No(4)
- consider group of 4
(0,1,1,1),(1,2,1,3),(3,2,1,?)
|| || ||
0*1+1=1 1*2+1=3 3*2+1=?=7
so the answers is 7 - 11 years agoHelpfull: Yes(0) No(4)
IBM Other Question
3,5,2,3.5,7,4,6,3,4.5,9,1.5,?
34,4,21,59,43,3,20,66,12,2,16, ?