if a line is having 10 dots in one line and second line having 8 dots if both the lines do not intersect ,find the possible no of triangles

• since we need to find all the possible combinations, the total no. of triangles with 2 vertices from 10-dots line and 1 from 8-dot line = 10C2*8C1
  Similarly, the total no. of triangles with 2 vertices from 8-dots line and 1 from 10-dot line=8C2*10C1
  total no. of triangles = (10C2*8C1)+(8C2*10C1)
• 11 years agoHelpfull: Yes(21) No(0)
• 10c2*8c1+8c2*10c1
• 11 years agoHelpfull: Yes(9) No(0)
• 10c2*8c1+8c2*10c1=388
• 11 years agoHelpfull: Yes(2) No(2)
• 10c2 * 8c1 +8c2 * 10c1
  =45*8+28*10
  =360+280= 640
• 11 years agoHelpfull: Yes(2) No(0)
• to creat triangle we reqire 3 dots...so, here we take 2 dots from 10 dots and 1 dots from 8 dots or 2 dots from 8 dots and 1 dots from 10 to creat triangle..dn the posssible no. of triangle is 10C2*8C1+8C2*10C1
  
• 11 years agoHelpfull: Yes(1) No(0)
• total points (10+8=18)
  as we have to make triangle we require three points always..
  so 10c3
  now on onse line there are 10 points but this point can be co-linear so we have to subtract it and similar with the other line
  
  so
  18c3-10c3-8c3=816-120-56=640 ans..
• 10 years agoHelpfull: Yes(1) No(0)
• 10P2*8P1+8P2*10P1
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• 18c2-10c2-8c2=80
• 11 years agoHelpfull: Yes(0) No(1)
• if 2 lines donot intersect so there will not be any possibility to make a triangle ...
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• sorry its my mistake....
  ans will be (10c1*8c2)+(10c2*8c1)
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• 18c3-8c3-10c3
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