Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

A. 210 B. 1050
C. 25200 D. 21400
E. None of these

• ans-(C)
  3 consonents r selected from 7 cons. is 7c3
  2 vowels are selected from 4 vowels is 4c2
  and these 5 words can arranged in 5!
  recquired no of ways - (7C3 x 4C2)*5!=(210 x 120) = 25200
• 12 years agoHelpfull: Yes(28) No(9)
• c:25200
  =7c3*4c2*5!
  
• 10 years agoHelpfull: Yes(4) No(2)
• no of words= 7c3*4c2
  = 35*6
  = 210
• 12 years agoHelpfull: Yes(2) No(19)
• Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)
  
  = (7C3 x 4C2)
  = 7 x 6 x 5 x 4 x 3
  3 x 2 x 1 2 x 1
  = 210.
  Number of groups, each having 3 consonants and 2 vowels = 210.
  
  Each group contains 5 letters.
  
  Number of ways of arranging
  5 letters among themselves = 5!
  = 5 x 4 x 3 x 2 x 1
  = 120.
  Required number of ways = (210 x 120) = 25200.
• 8 years agoHelpfull: Yes(0) No(0)