Q. In how many seconds does a 180m long train moving at 108kmph cross a platform of length 150 mtr?

Option
a) 11 second
b) 9 second
c) 8 second
d) 7 second

• 108 kmph = 108 *5/18 = 30 m/s
  The train is travelling at 30 m/s and it has to cover a distance of 180 m + 150 m ( Its length + Train length) = 330 m
  It will take a total of 330/ 30 = 11 seconds
  
  Answer is 11 seconds
• 10 years agoHelpfull: Yes(7) No(3)
• ANS:- 11 seconds....
  
  using speed of train = (length od plt frm + length of train) / (time taken)
• 9 years agoHelpfull: Yes(3) No(1)
• 330/(108*(5/18))=11 seconds (a)
• 6 years agoHelpfull: Yes(0) No(0)
• total d=330
  Speed=108*(5/18)=30
  t=330/30=11s
• 6 years agoHelpfull: Yes(0) No(0)
• 108 kmph = 108 *5/18 = 30 m/s
  The train is travelling at 30 m/s and it has to cover a distance of 180 m + 150 m ( Its length + Train length) = 330 m
  It will take a total of 330/ 30 = 11 seconds
  
  Answer is 11 seconds
• 4 years agoHelpfull: Yes(0) No(0)