what is the remainder when 2^39 is divided by 39?

• remainder will be 8.
  2^39 = (64)^6 * 8 /39
  25 ^ 6 * 8 /39
  (625)^3 *8 /39
  {1 ^3} * 8 /39
  => 8
• 10 years agoHelpfull: Yes(23) No(6)
• 2^12/39=4096/39 rem=1
  
  2^39=(2^12)^3*(2^3)/39 rem=(1^3)*(2^3)=8
  
  thus ans=8
• 10 years agoHelpfull: Yes(9) No(0)
• 
  =(2^39)/39
  =[((2^6)^6)*2^3]/39
  Apply Remainder the.. 64/39=25
  =(25^6)*2^3/39
  .
  .
  .
  .
  =8
  
• 10 years agoHelpfull: Yes(4) No(2)
• 2^39 will be written as 2^7*2^7*2^7*2^7*2^7*2^4
  when 2^7 divided by 39 leaves a remainder of 11
  so 11*11*11*11*11*16(when 2^4 divided by 3 leaves a remainder of 16)
  it can be written as 121*121*176
  large numbers so can be simplified as
  when 121 divided by 39 leaves remainder=4
  when 176 divided by 39 leaves remainder=20
  so 4*4*20=320
  320 divided by 39 leaves remainder=8
  Ans:8
• 10 years agoHelpfull: Yes(3) No(1)
• ans : 2
  (2^38*2^1)/39
  rem: (1*2)/39 // using fermet theorem
  =2
• 10 years agoHelpfull: Yes(2) No(5)
• 8
  see wolframalpha.com to solve
• 10 years agoHelpfull: Yes(1) No(1)
• 4)39(9
  36
  ------
  3
  2^3=8
  remainder=8
• 10 years agoHelpfull: Yes(1) No(1)
• Ans: 2 because (a^p)/p =a
• 8 years agoHelpfull: Yes(1) No(0)
• 2^39=2^6*2^6*2^6*2^6*2^6*2^6*2^3/39
  now using remainder theoram we get 25+25+25+25+25+25+8/39=2
  so remainder is 2
  
• 10 years agoHelpfull: Yes(0) No(3)
• reminder will be 8.
  2^39/39=((2^6)^6)*2^3/39
  so, 2^6/39= reminder will be 25
  so, (25^6)*2^3/39
  25^6/39= (25^2)^3/39= reminder 1
  so, (1^6)*2^3/39= reminder 39
• 10 years agoHelpfull: Yes(0) No(4)
• reminder will be 8.
  2^39/39=((2^6)^6)*2^3/39
  so, 2^6/39= reminder will be 25
  so, (25^6)*2^3/39
  25^6/39= (25^2)^3/39= reminder 1
  so, (1^6)*2^3/39= 1*8/39= reminder 8
• 10 years agoHelpfull: Yes(0) No(2)
• answer is 2 ......
• 10 years agoHelpfull: Yes(0) No(2)