If Jeffrey finishes both 15th highest and 15th lowest in a poker tournament, how many people were there in the tournament?
a) 27
b) 29
c) 30
d) 31
e) 32

• 15 from one side student =15
  15 fron last student 15
  now
  15+15=30
  30-1=29 as one student repeat in both above cases
  
  
• 11 years agoHelpfull: Yes(2) No(0)
• 15 highest
  and 15th lowest
  So 15+14=29
• 11 years agoHelpfull: Yes(1) No(0)
• 29 because to stay in the middle rank, it should odd number. To have 15, 29 is the only number which satisfies the condition
• 11 years agoHelpfull: Yes(1) No(0)
• ANSWER : 29
  Jeffrey = 15 highest ---> H15
  Jeffrey = 15 lowest ---> L15
  H15 = L15
  infront H15 has 14 peoples
  behind L1 has 14 peoples
  included Jefferey ---> 14+ jefferey + 14 = 29 peoples
• 11 years agoHelpfull: Yes(1) No(0)